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4.9x^2+6x=8
We move all terms to the left:
4.9x^2+6x-(8)=0
a = 4.9; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·4.9·(-8)
Δ = 192.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{192.8}}{2*4.9}=\frac{-6-\sqrt{192.8}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{192.8}}{2*4.9}=\frac{-6+\sqrt{192.8}}{9.8} $
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